15y^2=-2y+8

Solution for 15y^2=-2y+8 equation:

15y^2=-2y+8

We move all terms to the left:

15y^2-(-2y+8)=0

We get rid of parentheses

15y^2+2y-8=0

a = 15; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·15·(-8)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*15}=\frac{-24}{30}
=-4/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*15}=\frac{20}{30}
=2/3
$